The molar conductivity is maximum for the solution of concentration $...........$ $M$.

  • A
    $0.001$
  • B
    $0.005$
  • C
    $0.002$
  • D
    $0.004$

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The equivalent conductivities of $Ba^{2+}$ and $Cl^-$ ions at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. What is the equivalent conductivity of $BaCl_2$ at infinite dilution?

The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.

$A$ conductivity cell is filled with $0.01 \ M \ KCl$ and gives a resistance of $484 \ \Omega$. The conductivity of the solution is $0.00141 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ}C$. What is the cell constant (in $cm^{-1}$)?

The specific conductance of a saturated solution of silver bromide is $\kappa \ S \ cm^{-1}$. The limiting ionic conductances for $Ag^{+}$ and $Br^{-}$ are $x$ and $y$ $S \ cm^2 \ mol^{-1}$ respectively. Then the solubility of silver bromide (in $g/L$) will be $(Ag = 108, Br = 80)$.

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The resistance of a $1 \, N$ solution of a salt is $50 \, \Omega$. The two platinum electrodes in the solution are $2.1 \, cm$ apart and each has an area of $4.2 \, cm^2$. Calculate the equivalent conductivity of the solution.

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